5. Turniej MAKSY, Albatros 28.07.2015 r. 2: W Sadowski - M Głombińska, 2.0 MA | ||||||||||||
runda | przeciwnicy | rozd. | linia | kont rakt | gra | wist | lew | zapis | % | wynik bieżący | ||
NS | WE | |||||||||||
1 | 16:M Haldenby - C Haldenby, | 3 | NS | AAA | 50.00% | 50.00% | ||||||
4 | NS | AAA | 50.00% | 50.00% | ||||||||
2 | 15:E Krassowska - T Cesarz, | 5 | NS | 2 | N | 7 | = | +110 | 40.09% | 46.70% | ||
6 | NS | 4 | W | 10 | -3 | +300 | 99.59% | 59.92% | ||||
3 | 28:M Piechotta - M Frądczyk, 4.0 WP | 7 | NS | 2 | E | 2 | +2 | -170 | 10.32% | 50.00% | ||
8 | NS | 3 | E | J | +3 | -490 | 60.91% | 51.82% | ||||
4 | 27:D Krupnik - I Jagielski, 12.0 MA | 9 | NS | 4 | E | A | = | -620 | 45.05% | 50.85% | ||
10 | NS | 4 | W | 3 | -1 | +100 | 64.86% | 52.60% | ||||
5 | 26:J Skibicki - D Sobolewski, 4.0 PD | 11 | NS | 2 | W | 4 | +2 | -170 | 79.77% | 55.62% | ||
12 | NS | 3× | W | 4 | -2 | +300 | 69.82% | 57.04% | ||||
6 | 25:A Jurkiewicz - P Kowalewski, 5.0 MP/MA | 13 | NS | 3 | N | Q | +1 | +130 | 79.77% | 59.11% | ||
14 | NS | 3× | E | 3 | -3 | +500 | 89.68% | 61.66% | ||||
7 | 24:J Kowalewski - A Bułat, 2.5 MP | 15 | NS | 3 | W | 2 | = | -400 | 100.00% | 64.60% | ||
16 | NS | 3 | S | 8 | -2 | -100 | 9.09% | 60.64% | ||||
8 | 22:M Kaczmarek - E Horbaczewska, | 17 | NS | 4 | W | K | +1 | -450 | 0.00% | 56.60% | ||
18 | NS | 3 | E | 3 | -1 | +50 | 50.00% | 56.18% | ||||
9 | 21:K Tarabańska - G Szatkowski, KP | 19 | NS | 2 | N | A | = | +90 | 59.91% | 56.40% | ||
20 | NS | 2 | E | 2 | -4 | +400 | 89.68% | 58.25% | ||||
10 | 20:E Skopińska - P Witkowski, 21.0 MA | 21 | WE | 4 | W | 6 | = | +420 | 50.00% | 57.82% | ||
22 | WE | 2 | S | Q | = | -110 | 45.05% | 57.18% | ||||
11 | 19:H Kalotka-Kręglewska - T Kręglewski, 2.5 MA | 23 | WE | 2 | S | 9 | = | -110 | 15.27% | 55.18% | ||
24 | WE | 3 | N | 10 | +2 | -460 | 15.27% | 53.37% | ||||
12 | 18:A Popławski - J Uscki, 6.5 PD/WM | 25 | WE | 4 | S | A | -2 | +100 | 84.73% | 54.73% | ||
26 | WE | 4 | N | A | +1 | -650 | 0.41% | 52.47% | ||||
13 | 17:Z Dukindorf - R Dukindorf, MA | 27 | WE | 3 | W | 4 | = | +400 | 30.18% | 51.58% | ||
28 | WE | 5 | E | A | -2 | -100 | 89.68% | 53.04% | ||||
14 | 16:M Haldenby - C Haldenby, | 1 | WE | 0.00% | 51.08% | |||||||
2 | WE | 0.00% | 49.25% | |||||||||
SUMA: | 53.04% | |||||||||||
±: | ||||||||||||
WYNIK: | 53.04% | |||||||||||
MIEJSCE: | 10 |
Pary.4.1.0.23 ©Jan Romański'2005, strona wygenerowana 2015-07-28 o 23:39:05